134402441001 has 4 divisors (see below), whose sum is σ = 179203254672. Its totient is φ = 89601627332.

The previous prime is 134402440987. The next prime is 134402441011. The reversal of 134402441001 is 100144204431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100144204431 = 3 ⋅33381401477.

It is a cyclic number.

It is not a de Polignac number, because 134402441001 - 2⁷ = 134402440873 is a prime.

It is a super-2 number, since 2×134402441001² (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (134402441011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22400406831 + ... + 22400406836.

It is an arithmetic number, because the mean of its divisors is an integer number (44800813668).

Almost surely, 2^134402441001 is an apocalyptic number.

It is an amenable number.

134402441001 is a deficient number, since it is larger than the sum of its proper divisors (44800813671).

134402441001 is an equidigital number, since it uses as much as digits as its factorization.

134402441001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44800813670.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 134402441001 its reverse (100144204431), we get a palindrome (234546645432).

The spelling of 134402441001 in words is "one hundred thirty-four billion, four hundred two million, four hundred forty-one thousand, one".