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1344034144433 = 31169812553203
BaseRepresentation
bin10011100011101110101…
…011011000000010110001
311202111012001100202112102
4103203232223120002301
5134010040220110213
62505235112110145
7166050263505251
oct23435653300261
94674161322472
101344034144433
114790022656a2
12198596395355
1399984b948c6
14490a1837961
1524e64b79158
hex138eead80b1

1344034144433 has 8 divisors (see below), whose sum is σ = 1387472330496. Its totient is φ = 1300601098800.

The previous prime is 1344034144367. The next prime is 1344034144451. The reversal of 1344034144433 is 3344414304431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1344034144433 - 214 = 1344034128049 is a prime.

It is a super-3 number, since 3×13440341444333 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344037144433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 750191 + ... + 1803012.

It is an arithmetic number, because the mean of its divisors is an integer number (173434041312).

Almost surely, 21344034144433 is an apocalyptic number.

It is an amenable number.

1344034144433 is a deficient number, since it is larger than the sum of its proper divisors (43438186063).

1344034144433 is a wasteful number, since it uses less digits than its factorization.

1344034144433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2570215.

The product of its (nonzero) digits is 331776, while the sum is 38.

Adding to 1344034144433 its reverse (3344414304431), we get a palindrome (4688448448864).

The spelling of 1344034144433 in words is "one trillion, three hundred forty-four billion, thirty-four million, one hundred forty-four thousand, four hundred thirty-three".

Divisors: 1 31 16981 526411 2553203 79149293 43355940143 1344034144433