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13440400010331 = 37640019048111
BaseRepresentation
bin1100001110010101011001…
…0001001010110001011011
31202120220000120211001210020
43003211112101022301123
53230201414400312311
644330233505121523
72555015433050160
oct303452621126133
952526016731706
1013440400010331
114312050462888
121610a0a9292a3
137665691c21c8
14346739960067
15184937c2dc06
hexc395644ac5b

13440400010331 has 8 divisors (see below), whose sum is σ = 20480609539584. Its totient is φ = 7680228577320.

The previous prime is 13440400010327. The next prime is 13440400010333. The reversal of 13440400010331 is 13301000404431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13440400010331 - 22 = 13440400010327 is a prime.

It is a super-2 number, since 2×134404000103312 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13440400010333) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 320009524035 + ... + 320009524076.

It is an arithmetic number, because the mean of its divisors is an integer number (2560076192448).

Almost surely, 213440400010331 is an apocalyptic number.

13440400010331 is a deficient number, since it is larger than the sum of its proper divisors (7040209529253).

13440400010331 is an equidigital number, since it uses as much as digits as its factorization.

13440400010331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 640019048121.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 13440400010331 its reverse (13301000404431), we get a palindrome (26741400414762).

The spelling of 13440400010331 in words is "thirteen trillion, four hundred forty billion, four hundred million, ten thousand, three hundred thirty-one".

Divisors: 1 3 7 21 640019048111 1920057144333 4480133336777 13440400010331