1344040133 has 4 divisors (see below), whose sum is σ = 1380365580. Its totient is φ = 1307714688.

The previous prime is 1344040129. The next prime is 1344040151. The reversal of 1344040133 is 3310404431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 618168769 + 725871364 = 24863^2 + 26942^2 .

It is a cyclic number.

It is not a de Polignac number, because 1344040133 - 2² = 1344040129 is a prime.

It is a super-2 number, since 2×1344040133² = 3612887758229315378, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1344040099 and 1344040108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344040163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18162668 + ... + 18162741.

It is an arithmetic number, because the mean of its divisors is an integer number (345091395).

Almost surely, 2^1344040133 is an apocalyptic number.

It is an amenable number.

1344040133 is a deficient number, since it is larger than the sum of its proper divisors (36325447).

1344040133 is an equidigital number, since it uses as much as digits as its factorization.

1344040133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36325446.

The product of its (nonzero) digits is 1728, while the sum is 23.

The square root of 1344040133 is about 36661.1529142224. The cubic root of 1344040133 is about 1103.5806549574.

Adding to 1344040133 its reverse (3310404431), we get a palindrome (4654444564).

The spelling of 1344040133 in words is "one billion, three hundred forty-four million, forty thousand, one hundred thirty-three".