Base | Representation |
---|---|
bin | 11110100011110101101101… |
… | …010111110011011101000111 |
3 | 122121212220212000220110122010 |
4 | 132203311231113303131013 |
5 | 120104034344104102333 |
6 | 1153504243010305303 |
7 | 40211246344536060 |
oct | 3643655527633507 |
9 | 577786760813563 |
10 | 134404246550343 |
11 | 399095802a2330 |
12 | 130a853a288233 |
13 | 59cc35c715b23 |
14 | 25292b3673567 |
15 | 1081269b74563 |
hex | 7a3d6d5f3747 |
134404246550343 has 16 divisors (see below), whose sum is σ = 223425241019136. Its totient is φ = 69820387818240.
The previous prime is 134404246550263. The next prime is 134404246550383. The reversal of 134404246550343 is 343055642404431.
It is not a de Polignac number, because 134404246550343 - 28 = 134404246550087 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134404246550292 and 134404246550301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134404246550383) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 290918282346 + ... + 290918282807.
It is an arithmetic number, because the mean of its divisors is an integer number (13964077563696).
Almost surely, 2134404246550343 is an apocalyptic number.
134404246550343 is a deficient number, since it is larger than the sum of its proper divisors (89020994468793).
134404246550343 is a wasteful number, since it uses less digits than its factorization.
134404246550343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 581836565174.
The product of its (nonzero) digits is 8294400, while the sum is 48.
Adding to 134404246550343 its reverse (343055642404431), we get a palindrome (477459888954774).
The spelling of 134404246550343 in words is "one hundred thirty-four trillion, four hundred four billion, two hundred forty-six million, five hundred fifty thousand, three hundred forty-three".
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