13440445001 has 4 divisors (see below), whose sum is σ = 13443460992. Its totient is φ = 13437429012.

The previous prime is 13440444991. The next prime is 13440445003. The reversal of 13440445001 is 10054404431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10054404431 = 103 ⋅97615577.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13440445001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13440445003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1501301 + ... + 1510226.

It is an arithmetic number, because the mean of its divisors is an integer number (3360865248).

Almost surely, 2^13440445001 is an apocalyptic number.

It is an amenable number.

13440445001 is a deficient number, since it is larger than the sum of its proper divisors (3015991).

13440445001 is an equidigital number, since it uses as much as digits as its factorization.

13440445001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3015990.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 13440445001 its reverse (10054404431), we get a palindrome (23494849432).

The spelling of 13440445001 in words is "thirteen billion, four hundred forty million, four hundred forty-five thousand, one".