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1344045013213 = 7192006430459
BaseRepresentation
bin10011100011101111010…
…100110101100011011101
311202111012210210221200211
4103203233110311203131
5134010101010410323
62505240141052421
7166050455053540
oct23435724654335
94674183727624
101344045013213
11479008409561
12198599b57111
13999871cba36
14490a3066857
1524e65ac470d
hex138ef5358dd

1344045013213 has 4 divisors (see below), whose sum is σ = 1536051443680. Its totient is φ = 1152038582748.

The previous prime is 1344045013193. The next prime is 1344045013231. The reversal of 1344045013213 is 3123105404431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1344045013213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344045013253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96003215223 + ... + 96003215236.

It is an arithmetic number, because the mean of its divisors is an integer number (384012860920).

Almost surely, 21344045013213 is an apocalyptic number.

It is an amenable number.

1344045013213 is a deficient number, since it is larger than the sum of its proper divisors (192006430467).

1344045013213 is an equidigital number, since it uses as much as digits as its factorization.

1344045013213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 192006430466.

The product of its (nonzero) digits is 17280, while the sum is 31.

The spelling of 1344045013213 in words is "one trillion, three hundred forty-four billion, forty-five million, thirteen thousand, two hundred thirteen".

Divisors: 1 7 192006430459 1344045013213