1344098191093 has 4 divisors (see below), whose sum is σ = 1536112218400. Its totient is φ = 1152084163788.

The previous prime is 1344098191067. The next prime is 1344098191127. The reversal of 1344098191093 is 3901918904431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344098191093 - 2⁵ = 1344098191061 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1344098191093.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344098191043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 96007013643 + ... + 96007013656.

It is an arithmetic number, because the mean of its divisors is an integer number (384028054600).

Almost surely, 2^{1344098191093} is an apocalyptic number.

It is an amenable number.

1344098191093 is a deficient number, since it is larger than the sum of its proper divisors (192014027307).

1344098191093 is an equidigital number, since it uses as much as digits as its factorization.

1344098191093 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 192014027306.

The product of its (nonzero) digits is 839808, while the sum is 52.

The spelling of 1344098191093 in words is "one trillion, three hundred forty-four billion, ninety-eight million, one hundred ninety-one thousand, ninety-three".