13441042500531 has 32 divisors (see below), whose sum is σ = 19157259663360. Its totient is φ = 8361800832000.

The previous prime is 13441042500511. The next prime is 13441042500547. The reversal of 13441042500531 is 13500524014431.

13441042500531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 13441042500531 - 2⁵ = 13441042500499 is a prime.

It is a super-2 number, since 2×13441042500531² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13441042500492 and 13441042500501.

It is not an unprimeable number, because it can be changed into a prime (13441042500511) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 159516310 + ... + 159600548.

It is an arithmetic number, because the mean of its divisors is an integer number (598664364480).

Almost surely, 2^{13441042500531} is an apocalyptic number.

13441042500531 is a deficient number, since it is larger than the sum of its proper divisors (5716217162829).

13441042500531 is a wasteful number, since it uses less digits than its factorization.

13441042500531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140707.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 13441042500531 its reverse (13500524014431), we get a palindrome (26941566514962).

The spelling of 13441042500531 in words is "thirteen trillion, four hundred forty-one billion, forty-two million, five hundred thousand, five hundred thirty-one".