1344112536535 has 4 divisors (see below), whose sum is σ = 1612935043848. Its totient is φ = 1075290029224.

The previous prime is 1344112536517. The next prime is 1344112536583. The reversal of 1344112536535 is 5356352114431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1344112536535 - 2⁷ = 1344112536407 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1344112536491 and 1344112536500.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134411253649 + ... + 134411253658.

It is an arithmetic number, because the mean of its divisors is an integer number (403233760962).

Almost surely, 2^{1344112536535} is an apocalyptic number.

1344112536535 is a deficient number, since it is larger than the sum of its proper divisors (268822507313).

1344112536535 is an equidigital number, since it uses as much as digits as its factorization.

1344112536535 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 268822507312.

The product of its digits is 648000, while the sum is 43.

The spelling of 1344112536535 in words is "one trillion, three hundred forty-four billion, one hundred twelve million, five hundred thirty-six thousand, five hundred thirty-five".