134411420203 has 4 divisors (see below), whose sum is σ = 134414488600. Its totient is φ = 134408351808.

The previous prime is 134411420189. The next prime is 134411420303. The reversal of 134411420203 is 302024114431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 302024114431 = 13 ⋅23232624187.

It is a cyclic number.

It is not a de Polignac number, because 134411420203 - 2¹³ = 134411412011 is a prime.

It is a super-2 number, since 2×134411420203² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134411420303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1467525 + ... + 1556422.

It is an arithmetic number, because the mean of its divisors is an integer number (33603622150).

Almost surely, 2^134411420203 is an apocalyptic number.

134411420203 is a deficient number, since it is larger than the sum of its proper divisors (3068397).

134411420203 is an equidigital number, since it uses as much as digits as its factorization.

134411420203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3068396.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 134411420203 its reverse (302024114431), we get a palindrome (436435534634).

The spelling of 134411420203 in words is "one hundred thirty-four billion, four hundred eleven million, four hundred twenty thousand, two hundred three".