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134412051423623 = 293458744202811
BaseRepresentation
bin11110100011111100111110…
…100101000010000110000111
3122121220122222222011002222212
4132203330332211002012013
5120104201340131023443
61153512013300014035
740211643636056501
oct3643747645020607
9577818888132885
10134412051423623
1139911915a06126
12130a9b5809131b
135a000046b9b3c
142529814066d71
151081574e79618
hex7a3f3e942187

134412051423623 has 4 divisors (see below), whose sum is σ = 134870795626728. Its totient is φ = 133953307220520.

The previous prime is 134412051423619. The next prime is 134412051423659. The reversal of 134412051423623 is 326324150214431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134412051423623 - 22 = 134412051423619 is a prime.

It is a super-2 number, since 2×1344120514236232 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134412051423323) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 229372101113 + ... + 229372101698.

It is an arithmetic number, because the mean of its divisors is an integer number (33717698906682).

Almost surely, 2134412051423623 is an apocalyptic number.

134412051423623 is a deficient number, since it is larger than the sum of its proper divisors (458744203105).

134412051423623 is an equidigital number, since it uses as much as digits as its factorization.

134412051423623 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 458744203104.

The product of its (nonzero) digits is 414720, while the sum is 41.

The spelling of 134412051423623 in words is "one hundred thirty-four trillion, four hundred twelve billion, fifty-one million, four hundred twenty-three thousand, six hundred twenty-three".

Divisors: 1 293 458744202811 134412051423623