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13441215113223 = 34480405037741
BaseRepresentation
bin1100001110011000011011…
…0110100010100000000111
31202120222010101120120202020
43003212012312202200013
53230210102032110343
644330450423414223
72555044561235352
oct303460666424007
952528111516666
1013441215113223
114312429579737
121610bb78b4373
13766669032501
143467b5cdb299
1518498458ab83
hexc3986da2807

13441215113223 has 4 divisors (see below), whose sum is σ = 17921620150968. Its totient is φ = 8960810075480.

The previous prime is 13441215113167. The next prime is 13441215113297. The reversal of 13441215113223 is 32231151214431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13441215113223 - 221 = 13441213016071 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13441215112223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2240202518868 + ... + 2240202518873.

It is an arithmetic number, because the mean of its divisors is an integer number (4480405037742).

Almost surely, 213441215113223 is an apocalyptic number.

13441215113223 is a deficient number, since it is larger than the sum of its proper divisors (4480405037745).

13441215113223 is an equidigital number, since it uses as much as digits as its factorization.

13441215113223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4480405037744.

The product of its digits is 17280, while the sum is 33.

Adding to 13441215113223 its reverse (32231151214431), we get a palindrome (45672366327654).

The spelling of 13441215113223 in words is "thirteen trillion, four hundred forty-one billion, two hundred fifteen million, one hundred thirteen thousand, two hundred twenty-three".

Divisors: 1 3 4480405037741 13441215113223