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134414012233 = 314711427103
BaseRepresentation
bin111110100101110110…
…0110000111101001001
3110211221112200022002101
41331023230300331021
54200234441342413
6141425434433401
712465622152454
oct1751354607511
9424845608071
10134414012233
1152006229926
1222072b92861
13c8a15026a7
1467117d049b
15376a618edd
hex1f4bb30f49

134414012233 has 4 divisors (see below), whose sum is σ = 134414754048. Its totient is φ = 134413270420.

The previous prime is 134414012221. The next prime is 134414012237. The reversal of 134414012233 is 332210414431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 134414012233 - 213 = 134414004041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (134414012237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101160 + ... + 528262.

It is an arithmetic number, because the mean of its divisors is an integer number (33603688512).

Almost surely, 2134414012233 is an apocalyptic number.

It is an amenable number.

134414012233 is a deficient number, since it is larger than the sum of its proper divisors (741815).

134414012233 is an equidigital number, since it uses as much as digits as its factorization.

134414012233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 741814.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 134414012233 its reverse (332210414431), we get a palindrome (466624426664).

The spelling of 134414012233 in words is "one hundred thirty-four billion, four hundred fourteen million, twelve thousand, two hundred thirty-three".

Divisors: 1 314711 427103 134414012233