Base | Representation |
---|---|
bin | 1100001110011001001000… |
… | …1011000110010011110111 |
3 | 1202120222121121222110222100 |
4 | 3003212102023012103313 |
5 | 3230210444143132101 |
6 | 44330521330433143 |
7 | 2555052355550226 |
oct | 303462213062367 |
9 | 52528547873870 |
10 | 13441405052151 |
11 | 431251680a65a |
12 | 161104b4327b3 |
13 | 7666994a61cb |
14 | 3467d3220cbd |
15 | 1849960a8e86 |
hex | c39922c64f7 |
13441405052151 has 12 divisors (see below), whose sum is σ = 19705144389112. Its totient is φ = 8827191377136.
The previous prime is 13441405052143. The next prime is 13441405052209. The reversal of 13441405052151 is 15125050414431.
13441405052151 is a `hidden beast` number, since 1 + 3 + 4 + 4 + 140 + 505 + 2 + 1 + 5 + 1 = 666.
13441405052151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13441405052151 - 23 = 13441405052143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13441405052111) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11145443056 + ... + 11145444261.
Almost surely, 213441405052151 is an apocalyptic number.
13441405052151 is a deficient number, since it is larger than the sum of its proper divisors (6263739336961).
13441405052151 is a wasteful number, since it uses less digits than its factorization.
13441405052151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22290887390 (or 22290887387 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 36.
Adding to 13441405052151 its reverse (15125050414431), we get a palindrome (28566455466582).
The spelling of 13441405052151 in words is "thirteen trillion, four hundred forty-one billion, four hundred five million, fifty-two thousand, one hundred fifty-one".
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