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1344143401 = 1951688951
BaseRepresentation
bin101000000011110…
…0000000000101001
310110200020120002221
41100013200000221
510223100042101
6341213354041
745211013266
oct12007400051
93420216087
101344143401
1162a808917
12316198921
13185622733
14ca73226d
157d00eaa1
hex501e0029

1344143401 has 4 divisors (see below), whose sum is σ = 1344834304. Its totient is φ = 1343452500.

The previous prime is 1344143393. The next prime is 1344143413. The reversal of 1344143401 is 1043414431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1344143401 - 23 = 1344143393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344143431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 342525 + ... + 346426.

It is an arithmetic number, because the mean of its divisors is an integer number (336208576).

Almost surely, 21344143401 is an apocalyptic number.

It is an amenable number.

1344143401 is a deficient number, since it is larger than the sum of its proper divisors (690903).

1344143401 is an equidigital number, since it uses as much as digits as its factorization.

1344143401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 690902.

The product of its (nonzero) digits is 2304, while the sum is 25.

The square root of 1344143401 is about 36662.5612989600. The cubic root of 1344143401 is about 1103.6089184111.

Adding to 1344143401 its reverse (1043414431), we get a palindrome (2387557832).

The spelling of 1344143401 in words is "one billion, three hundred forty-four million, one hundred forty-three thousand, four hundred one".

Divisors: 1 1951 688951 1344143401