13442104121 has 4 divisors (see below), whose sum is σ = 13580682612. Its totient is φ = 13303525632.

The previous prime is 13442104057. The next prime is 13442104147. The reversal of 13442104121 is 12140124431.

13442104121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 12140124431 = 23 ⋅527831497.

It can be written as a sum of positive squares in 2 ways, for example, as 9825765625 + 3616338496 = 99125^2 + 60136^2 .

It is a cyclic number.

It is not a de Polignac number, because 13442104121 - 2⁶ = 13442104057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13442104321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69289100 + ... + 69289293.

It is an arithmetic number, because the mean of its divisors is an integer number (3395170653).

Almost surely, 2^13442104121 is an apocalyptic number.

It is an amenable number.

13442104121 is a deficient number, since it is larger than the sum of its proper divisors (138578491).

13442104121 is an equidigital number, since it uses as much as digits as its factorization.

13442104121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138578490.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13442104121 its reverse (12140124431), we get a palindrome (25582228552).

The spelling of 13442104121 in words is "thirteen billion, four hundred forty-two million, one hundred four thousand, one hundred twenty-one".