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134421151999 = 235844397913
BaseRepresentation
bin111110100110000100…
…0000000000011111111
3110211222001010001000011
41331030020000003333
54200243303330444
6141430251444051
712466036640221
oct1751410000377
9424861101004
10134421151999
115200a266062
1222075456627
13c8a2b323c4
14671272c411
15376b079734
hex1f4c2000ff

134421151999 has 4 divisors (see below), whose sum is σ = 140265549936. Its totient is φ = 128576754064.

The previous prime is 134421151967. The next prime is 134421152077. The reversal of 134421151999 is 999151124431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134421151999 - 25 = 134421151967 is a prime.

It is a super-2 number, since 2×1344211519992 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134421151919) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2922198934 + ... + 2922198979.

It is an arithmetic number, because the mean of its divisors is an integer number (35066387484).

Almost surely, 2134421151999 is an apocalyptic number.

134421151999 is a deficient number, since it is larger than the sum of its proper divisors (5844397937).

134421151999 is an equidigital number, since it uses as much as digits as its factorization.

134421151999 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5844397936.

The product of its digits is 349920, while the sum is 49.

The spelling of 134421151999 in words is "one hundred thirty-four billion, four hundred twenty-one million, one hundred fifty-one thousand, nine hundred ninety-nine".

Divisors: 1 23 5844397913 134421151999