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13442120543 = 22216052283
BaseRepresentation
bin11001000010011011…
…00111101101011111
31021200210201110211102
430201031213231133
5210012140324133
610101503143315
7654052065545
oct144115475537
937623643742
1013442120543
1157787aa135
1227318a4b3b
131362b700a7
14917375d95
1553a1857e8
hex321367b5f

13442120543 has 4 divisors (see below), whose sum is σ = 13448175048. Its totient is φ = 13436066040.

The previous prime is 13442120539. The next prime is 13442120561. The reversal of 13442120543 is 34502124431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34502124431 = 334710308373.

It is a cyclic number.

It is not a de Polignac number, because 13442120543 - 22 = 13442120539 is a prime.

It is a super-2 number, since 2×134421205432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13442120143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3023921 + ... + 3028362.

It is an arithmetic number, because the mean of its divisors is an integer number (3362043762).

Almost surely, 213442120543 is an apocalyptic number.

13442120543 is a deficient number, since it is larger than the sum of its proper divisors (6054505).

13442120543 is an equidigital number, since it uses as much as digits as its factorization.

13442120543 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6054504.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 13442120543 its reverse (34502124431), we get a palindrome (47944244974).

The spelling of 13442120543 in words is "thirteen billion, four hundred forty-two million, one hundred twenty thousand, five hundred forty-three".

Divisors: 1 2221 6052283 13442120543