Base | Representation |
---|---|
bin | 10011100011111001010… |
… | …011001010011001000010 |
3 | 11202111122110200100201112 |
4 | 103203321103022121002 |
5 | 134010421330041214 |
6 | 2505304515403322 |
7 | 166054556264516 |
oct | 23437123123102 |
9 | 4674573610645 |
10 | 1344212346434 |
11 | 47909390a481 |
12 | 198625bb3542 |
13 | 999b2a89289 |
14 | 490bb384146 |
15 | 24e75629a3e |
hex | 138f94ca642 |
1344212346434 has 4 divisors (see below), whose sum is σ = 2016318519654. Its totient is φ = 672106173216.
The previous prime is 1344212346391. The next prime is 1344212346439. The reversal of 1344212346434 is 4346432124431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1317249721225 + 26962625209 = 1147715^2 + 164203^2 .
It is a junction number, because it is equal to n+sod(n) for n = 1344212346391 and 1344212346400.
It is not an unprimeable number, because it can be changed into a prime (1344212346439) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 336053086607 + ... + 336053086610.
Almost surely, 21344212346434 is an apocalyptic number.
1344212346434 is a deficient number, since it is larger than the sum of its proper divisors (672106173220).
1344212346434 is an equidigital number, since it uses as much as digits as its factorization.
1344212346434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 672106173219.
The product of its digits is 663552, while the sum is 41.
The spelling of 1344212346434 in words is "one trillion, three hundred forty-four billion, two hundred twelve million, three hundred forty-six thousand, four hundred thirty-four".
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