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1344233002034 = 21351701269309
BaseRepresentation
bin10011100011111010100…
…001111101010000110010
311202111200220112202212202
4103203322201331100302
5134010442122031114
62505310534223202
7166055226664106
oct23437241752062
94674626482782
101344233002034
114790a453831a
12198630ab4b02
13999b713bc20
14490bdddd906
1524e77359cde
hex138fa87d432

1344233002034 has 8 divisors (see below), whose sum is σ = 2171453311020. Its totient is φ = 620415231696.

The previous prime is 1344233001913. The next prime is 1344233002109. The reversal of 1344233002034 is 4302003324431.

It can be written as a sum of positive squares in 2 ways, for example, as 1341420290809 + 2812711225 = 1158197^2 + 53035^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1344233001988 and 1344233002006.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25850634629 + ... + 25850634680.

Almost surely, 21344233002034 is an apocalyptic number.

1344233002034 is a deficient number, since it is larger than the sum of its proper divisors (827220308986).

1344233002034 is a wasteful number, since it uses less digits than its factorization.

1344233002034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51701269324.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 1344233002034 its reverse (4302003324431), we get a palindrome (5646236326465).

The spelling of 1344233002034 in words is "one trillion, three hundred forty-four billion, two hundred thirty-three million, two thousand, thirty-four".

Divisors: 1 2 13 26 51701269309 103402538618 672116501017 1344233002034