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1344240343 = 2934587851
BaseRepresentation
bin101000000011111…
…0111101011010111
310110200102111002101
41100013313223113
510223111142333
6341215422531
745211566025
oct12007675327
93420374071
101344240343
1162a874736
12316224a47
131856578b4
14ca759715
157d02d67d
hex501f7ad7

1344240343 has 4 divisors (see below), whose sum is σ = 1348828488. Its totient is φ = 1339652200.

The previous prime is 1344240257. The next prime is 1344240349. The reversal of 1344240343 is 3430424431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1344240343 - 213 = 1344232151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344240349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2293633 + ... + 2294218.

It is an arithmetic number, because the mean of its divisors is an integer number (337207122).

Almost surely, 21344240343 is an apocalyptic number.

1344240343 is a deficient number, since it is larger than the sum of its proper divisors (4588145).

1344240343 is an equidigital number, since it uses as much as digits as its factorization.

1344240343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4588144.

The product of its (nonzero) digits is 13824, while the sum is 28.

The square root of 1344240343 is about 36663.8833595134. The cubic root of 1344240343 is about 1103.6354491825.

Adding to 1344240343 its reverse (3430424431), we get a palindrome (4774664774).

The spelling of 1344240343 in words is "one billion, three hundred forty-four million, two hundred forty thousand, three hundred forty-three".

Divisors: 1 293 4587851 1344240343