1344240400003 has 4 divisors (see below), whose sum is σ = 1414989894760. Its totient is φ = 1273490905248.

The previous prime is 1344240399973. The next prime is 1344240400007. The reversal of 1344240400003 is 3000040424431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1344240400003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1344240400007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35374747350 + ... + 35374747387.

It is an arithmetic number, because the mean of its divisors is an integer number (353747473690).

Almost surely, 2^{1344240400003} is an apocalyptic number.

1344240400003 is a deficient number, since it is larger than the sum of its proper divisors (70749494757).

1344240400003 is an equidigital number, since it uses as much as digits as its factorization.

1344240400003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70749494756.

The product of its (nonzero) digits is 4608, while the sum is 25.

Adding to 1344240400003 its reverse (3000040424431), we get a palindrome (4344280824434).

The spelling of 1344240400003 in words is "one trillion, three hundred forty-four billion, two hundred forty million, four hundred thousand, three".