134424440411551 has 4 divisors (see below), whose sum is σ = 134441062707312. Its totient is φ = 134407818115792.

The previous prime is 134424440411413. The next prime is 134424440411561. The reversal of 134424440411551 is 155114044424431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134424440411551 - 2⁹ = 134424440411039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134424440411498 and 134424440411507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134424440411561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8311135750 + ... + 8311151923.

It is an arithmetic number, because the mean of its divisors is an integer number (33610265676828).

Almost surely, 2^{134424440411551} is an apocalyptic number.

134424440411551 is a deficient number, since it is larger than the sum of its proper divisors (16622295761).

134424440411551 is an equidigital number, since it uses as much as digits as its factorization.

134424440411551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16622295760.

The product of its (nonzero) digits is 614400, while the sum is 43.

Adding to 134424440411551 its reverse (155114044424431), we get a palindrome (289538484835982).

The spelling of 134424440411551 in words is "one hundred thirty-four trillion, four hundred twenty-four billion, four hundred forty million, four hundred eleven thousand, five hundred fifty-one".