Base | Representation |
---|---|
bin | 11001000010011111… |
… | …10110100010000001 |
3 | 1021200211211012021212 |
4 | 30201033312202001 |
5 | 210012313034122 |
6 | 10101523455505 |
7 | 654060053222 |
oct | 144117664201 |
9 | 37624735255 |
10 | 13442705537 |
11 | 57790696a8 |
12 | 2731b27595 |
13 | 1363016441 |
14 | 917489249 |
15 | 53a24dce2 |
hex | 3213f6881 |
13442705537 has 4 divisors (see below), whose sum is σ = 13755326640. Its totient is φ = 13130084436.
The previous prime is 13442705531. The next prime is 13442705543. The reversal of 13442705537 is 73550724431.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is an interprime number because it is at equal distance from previous prime (13442705531) and next prime (13442705543).
It is a cyclic number.
It is not a de Polignac number, because 13442705537 - 26 = 13442705473 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13442705494 and 13442705503.
It is not an unprimeable number, because it can be changed into a prime (13442705531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156310487 + ... + 156310572.
It is an arithmetic number, because the mean of its divisors is an integer number (3438831660).
Almost surely, 213442705537 is an apocalyptic number.
It is an amenable number.
13442705537 is a deficient number, since it is larger than the sum of its proper divisors (312621103).
13442705537 is an equidigital number, since it uses as much as digits as its factorization.
13442705537 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 312621102.
The product of its (nonzero) digits is 352800, while the sum is 41.
The spelling of 13442705537 in words is "thirteen billion, four hundred forty-two million, seven hundred five thousand, five hundred thirty-seven".
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