Base | Representation |
---|---|
bin | 1100001110011111100110… |
… | …1010001001000011100111 |
3 | 1202121011002121221010020020 |
4 | 3003213321222021003213 |
5 | 3230223023124234421 |
6 | 44331405511210223 |
7 | 2555143400124366 |
oct | 303477152110347 |
9 | 52534077833206 |
10 | 13443141243111 |
11 | 4313227851618 |
12 | 1611454976973 |
13 | 7668b50b4638 |
14 | 346919a477dd |
15 | 184a4870adc6 |
hex | c39f9a890e7 |
13443141243111 has 8 divisors (see below), whose sum is σ = 17924212732800. Its totient is φ = 8962081957752.
The previous prime is 13443141243061. The next prime is 13443141243149. The reversal of 13443141243111 is 11134214134431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13443141243111 - 211 = 13443141241063 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13443141243211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62785 + ... + 5185578.
It is an arithmetic number, because the mean of its divisors is an integer number (2240526591600).
Almost surely, 213443141243111 is an apocalyptic number.
13443141243111 is a deficient number, since it is larger than the sum of its proper divisors (4481071489689).
13443141243111 is an equidigital number, since it uses as much as digits as its factorization.
13443141243111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6102165.
The product of its digits is 13824, while the sum is 33.
Adding to 13443141243111 its reverse (11134214134431), we get a palindrome (24577355377542).
The spelling of 13443141243111 in words is "thirteen trillion, four hundred forty-three billion, one hundred forty-one million, two hundred forty-three thousand, one hundred eleven".
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