Base | Representation |
---|---|
bin | 11001000010100011… |
… | …10110100101011001 |
3 | 1021200212210211202221 |
4 | 30201101312211121 |
5 | 210012431330131 |
6 | 10101543024041 |
7 | 654064366333 |
oct | 144121664531 |
9 | 37625724687 |
10 | 13443230041 |
11 | 577939777a |
12 | 273213b021 |
13 | 136316b0b7 |
14 | 917584453 |
15 | 53a304411 |
hex | 321476959 |
13443230041 has 8 divisors (see below), whose sum is σ = 13610842560. Its totient is φ = 13275752112.
The previous prime is 13443230039. The next prime is 13443230057. The reversal of 13443230041 is 14003234431.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13443230041 - 21 = 13443230039 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13443229988 and 13443230015.
It is not an unprimeable number, because it can be changed into a prime (13443231041) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 175395 + ... + 240103.
It is an arithmetic number, because the mean of its divisors is an integer number (1701355320).
Almost surely, 213443230041 is an apocalyptic number.
It is an amenable number.
13443230041 is a deficient number, since it is larger than the sum of its proper divisors (167612519).
13443230041 is an equidigital number, since it uses as much as digits as its factorization.
13443230041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67295.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 13443230041 its reverse (14003234431), we get a palindrome (27446464472).
The spelling of 13443230041 in words is "thirteen billion, four hundred forty-three million, two hundred thirty thousand, forty-one".
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