1344401041135 has 4 divisors (see below), whose sum is σ = 1613281249368. Its totient is φ = 1075520832904.

The previous prime is 1344401041133. The next prime is 1344401041141. The reversal of 1344401041135 is 5311401044431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1344401041135 - 2¹ = 1344401041133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1344401041097 and 1344401041106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344401041133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134440104109 + ... + 134440104118.

It is an arithmetic number, because the mean of its divisors is an integer number (403320312342).

Almost surely, 2^{1344401041135} is an apocalyptic number.

1344401041135 is a deficient number, since it is larger than the sum of its proper divisors (268880208233).

1344401041135 is an equidigital number, since it uses as much as digits as its factorization.

1344401041135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 268880208232.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 1344401041135 its reverse (5311401044431), we get a palindrome (6655802085566).

The spelling of 1344401041135 in words is "one trillion, three hundred forty-four billion, four hundred one million, forty-one thousand, one hundred thirty-five".