Base | Representation |
---|---|
bin | 11110100100010111000111… |
… | …000001010100111101000111 |
3 | 122122000100102102222001112012 |
4 | 132210113013001110331013 |
5 | 120110131321222033210 |
6 | 1153532533432044435 |
7 | 40213656156012203 |
oct | 3644270701247507 |
9 | 578010372861465 |
10 | 134440110346055 |
11 | 39922804497918 |
12 | 130b3488b3371b |
13 | 5a02856898217 |
14 | 252ad16793b03 |
15 | 108216847e305 |
hex | 7a45c7054f47 |
134440110346055 has 4 divisors (see below), whose sum is σ = 161328132415272. Its totient is φ = 107552088276840.
The previous prime is 134440110346021. The next prime is 134440110346097. The reversal of 134440110346055 is 550643011044431.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 134440110346055 - 226 = 134440043237191 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13444011034601 + ... + 13444011034610.
It is an arithmetic number, because the mean of its divisors is an integer number (40332033103818).
Almost surely, 2134440110346055 is an apocalyptic number.
134440110346055 is a deficient number, since it is larger than the sum of its proper divisors (26888022069217).
134440110346055 is an equidigital number, since it uses as much as digits as its factorization.
134440110346055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26888022069216.
The product of its (nonzero) digits is 345600, while the sum is 41.
The spelling of 134440110346055 in words is "one hundred thirty-four trillion, four hundred forty billion, one hundred ten million, three hundred forty-six thousand, fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •