Base | Representation |
---|---|
bin | 10011100100000100101… |
… | …110011010100101100011 |
3 | 11202112010211101101220112 |
4 | 103210010232122211203 |
5 | 134011314413240120 |
6 | 2505335524201535 |
7 | 166062404535140 |
oct | 23440456324543 |
9 | 4675124341815 |
10 | 1344404040035 |
11 | 479182039741 |
12 | 19867a2392ab |
13 | 99a136c5844 |
14 | 490d8a033c7 |
15 | 24e87392bc5 |
hex | 13904b9a963 |
1344404040035 has 16 divisors (see below), whose sum is σ = 1843956428736. Its totient is φ = 921775897728.
The previous prime is 1344404040017. The next prime is 1344404040037. The reversal of 1344404040035 is 5300404044431.
It is a de Polignac number, because none of the positive numbers 2k-1344404040035 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1344404039983 and 1344404040010.
It is not an unprimeable number, because it can be changed into a prime (1344404040037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1783244 + ... + 2422553.
It is an arithmetic number, because the mean of its divisors is an integer number (115247276796).
Almost surely, 21344404040035 is an apocalyptic number.
1344404040035 is a deficient number, since it is larger than the sum of its proper divisors (499552388701).
1344404040035 is an equidigital number, since it uses as much as digits as its factorization.
1344404040035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4214942.
The product of its (nonzero) digits is 46080, while the sum is 32.
Adding to 1344404040035 its reverse (5300404044431), we get a palindrome (6644808084466).
The spelling of 1344404040035 in words is "one trillion, three hundred forty-four billion, four hundred four million, forty thousand, thirty-five".
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