Base | Representation |
---|---|
bin | 10011100100000101010… |
… | …100110011100111100001 |
3 | 11202112011112022201010012 |
4 | 103210011110303213201 |
5 | 134011330002312113 |
6 | 2505340524014305 |
7 | 166062556222220 |
oct | 23440524634741 |
9 | 4675145281105 |
10 | 1344414104033 |
11 | 4791877929a0 |
12 | 198681691395 |
13 | 99a1580a580 |
14 | 490da0a2cb7 |
15 | 24e881ceaa8 |
hex | 139055339e1 |
1344414104033 has 32 divisors (see below), whose sum is σ = 1822959758592. Its totient is φ = 957436704000.
The previous prime is 1344414104017. The next prime is 1344414104071. The reversal of 1344414104033 is 3304014144431.
It is not a de Polignac number, because 1344414104033 - 24 = 1344414104017 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1344414104003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6547766 + ... + 6749967.
It is an arithmetic number, because the mean of its divisors is an integer number (56967492456).
Almost surely, 21344414104033 is an apocalyptic number.
1344414104033 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1344414104033 is a deficient number, since it is larger than the sum of its proper divisors (478545654559).
1344414104033 is a wasteful number, since it uses less digits than its factorization.
1344414104033 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13297865.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 1344414104033 its reverse (3304014144431), we get a palindrome (4648428248464).
The spelling of 1344414104033 in words is "one trillion, three hundred forty-four billion, four hundred fourteen million, one hundred four thousand, thirty-three".
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