13444224433121 has 4 divisors (see below), whose sum is σ = 13574750884032. Its totient is φ = 13313697982212.

The previous prime is 13444224433111. The next prime is 13444224433153. The reversal of 13444224433121 is 12133442244431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13444224433121 - 2¹⁴ = 13444224416737 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13444224433111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65263225301 + ... + 65263225506.

It is an arithmetic number, because the mean of its divisors is an integer number (3393687721008).

Almost surely, 2^{13444224433121} is an apocalyptic number.

It is an amenable number.

13444224433121 is a deficient number, since it is larger than the sum of its proper divisors (130526450911).

13444224433121 is a wasteful number, since it uses less digits than its factorization.

13444224433121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 130526450910.

The product of its digits is 221184, while the sum is 38.

Adding to 13444224433121 its reverse (12133442244431), we get a palindrome (25577666677552).

The spelling of 13444224433121 in words is "thirteen trillion, four hundred forty-four billion, two hundred twenty-four million, four hundred thirty-three thousand, one hundred twenty-one".