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1344433434103 = 2441550771583
BaseRepresentation
bin10011100100000110011…
…110100010110111110111
311202112012212200202222201
4103210012132202313313
5134011344424342403
62505342454205331
7166063212431134
oct23440636426767
94675185622881
101344433434103
11479197695961
12198688053847
1399a19817a96
14490dc89558b
1524e89c4c21d
hex139067a2df7

1344433434103 has 4 divisors (see below), whose sum is σ = 1344984208128. Its totient is φ = 1343882660080.

The previous prime is 1344433434079. The next prime is 1344433434163. The reversal of 1344433434103 is 3014343344431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1344433434103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1344433434163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 275383351 + ... + 275388232.

It is an arithmetic number, because the mean of its divisors is an integer number (336246052032).

Almost surely, 21344433434103 is an apocalyptic number.

1344433434103 is a deficient number, since it is larger than the sum of its proper divisors (550774025).

1344433434103 is an equidigital number, since it uses as much as digits as its factorization.

1344433434103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 550774024.

The product of its (nonzero) digits is 248832, while the sum is 37.

Adding to 1344433434103 its reverse (3014343344431), we get a palindrome (4358776778534).

The spelling of 1344433434103 in words is "one trillion, three hundred forty-four billion, four hundred thirty-three million, four hundred thirty-four thousand, one hundred three".

Divisors: 1 2441 550771583 1344433434103