13444400444431 has 4 divisors (see below), whose sum is σ = 14666618666664. Its totient is φ = 12222182222200.

The previous prime is 13444400444399. The next prime is 13444400444459.

13444400444431 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13444400444431 - 2⁵ = 13444400444399 is a prime.

It is a super-2 number, since 2×13444400444431² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13444400444231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 611109111100 + ... + 611109111121.

It is an arithmetic number, because the mean of its divisors is an integer number (3666654666666).

Almost surely, 2^{13444400444431} is an apocalyptic number.

13444400444431 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13444400444431 is a deficient number, since it is larger than the sum of its proper divisors (1222218222233).

13444400444431 is a wasteful number, since it uses less digits than its factorization.

13444400444431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1222218222232.

The product of its (nonzero) digits is 589824, while the sum is 40.

It can be divided in two parts, 13444400 and 444431, that added together give a palindrome (13888831).

The spelling of 13444400444431 in words is "thirteen trillion, four hundred forty-four billion, four hundred million, four hundred forty-four thousand, four hundred thirty-one".