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13445140012555 = 52689028002511
BaseRepresentation
bin1100001110100111000011…
…0010110101111000001011
31202121100020220222010110011
43003221300302311320023
53230241121320400210
644332340111532351
72555244050312506
oct303516062657013
952540226863404
1013445140012555
114314063028699
12161191222a0b7
13766b4321a854
14346a692a213d
15184b13e28d8a
hexc3a70cb5e0b

13445140012555 has 4 divisors (see below), whose sum is σ = 16134168015072. Its totient is φ = 10756112010040.

The previous prime is 13445140012531. The next prime is 13445140012559. The reversal of 13445140012555 is 55521004154431.

13445140012555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13445140012555 - 221 = 13445137915403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13445140012559) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1344514001251 + ... + 1344514001260.

It is an arithmetic number, because the mean of its divisors is an integer number (4033542003768).

Almost surely, 213445140012555 is an apocalyptic number.

13445140012555 is a deficient number, since it is larger than the sum of its proper divisors (2689028002517).

13445140012555 is an equidigital number, since it uses as much as digits as its factorization.

13445140012555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2689028002516.

The product of its (nonzero) digits is 240000, while the sum is 40.

Adding to 13445140012555 its reverse (55521004154431), we get a palindrome (68966144166986).

The spelling of 13445140012555 in words is "thirteen trillion, four hundred forty-five billion, one hundred forty million, twelve thousand, five hundred fifty-five".

Divisors: 1 5 2689028002511 13445140012555