Base | Representation |
---|---|
bin | 1100001110100111000011… |
… | …0010110101110111110011 |
3 | 1202121100020220222010102021 |
4 | 3003221300302311313303 |
5 | 3230241121320400111 |
6 | 44332340111532311 |
7 | 2555244050312443 |
oct | 303516062656763 |
9 | 52540226863367 |
10 | 13445140012531 |
11 | 4314063028677 |
12 | 161191222a097 |
13 | 766b4321a836 |
14 | 346a692a2123 |
15 | 184b13e28d71 |
hex | c3a70cb5df3 |
13445140012531 has 2 divisors, whose sum is σ = 13445140012532. Its totient is φ = 13445140012530.
The previous prime is 13445140012529. The next prime is 13445140012559. The reversal of 13445140012531 is 13521004154431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13445140012531 - 21 = 13445140012529 is a prime.
It is a super-2 number, since 2×134451400125312 (a number of 27 digits) contains 22 as substring.
Together with 13445140012529, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13445140013531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6722570006265 + 6722570006266.
It is an arithmetic number, because the mean of its divisors is an integer number (6722570006266).
Almost surely, 213445140012531 is an apocalyptic number.
13445140012531 is a deficient number, since it is larger than the sum of its proper divisors (1).
13445140012531 is an equidigital number, since it uses as much as digits as its factorization.
13445140012531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 13445140012531 its reverse (13521004154431), we get a palindrome (26966144166962).
The spelling of 13445140012531 in words is "thirteen trillion, four hundred forty-five billion, one hundred forty million, twelve thousand, five hundred thirty-one".
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