134451544112042 has 4 divisors (see below), whose sum is σ = 201677316168066. Its totient is φ = 67225772056020.

The previous prime is 134451544111981. The next prime is 134451544112077. The reversal of 134451544112042 is 240211445154431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 106390993789201 + 28060550322841 = 10314601^2 + 5297221^2 .

It is a super-3 number, since 3×134451544112042³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33612886028009 + ... + 33612886028012.

Almost surely, 2^{134451544112042} is an apocalyptic number.

134451544112042 is a deficient number, since it is larger than the sum of its proper divisors (67225772056024).

134451544112042 is an equidigital number, since it uses as much as digits as its factorization.

134451544112042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67225772056023.

The product of its (nonzero) digits is 307200, while the sum is 41.

Adding to 134451544112042 its reverse (240211445154431), we get a palindrome (374662989266473).

The spelling of 134451544112042 in words is "one hundred thirty-four trillion, four hundred fifty-one billion, five hundred forty-four million, one hundred twelve thousand, forty-two".