Base | Representation |
---|---|
bin | 10011100100010001000… |
… | …011111010001011011101 |
3 | 11202112200020211010001102 |
4 | 103210101003322023131 |
5 | 134012230404013203 |
6 | 2505412240122445 |
7 | 166100466634055 |
oct | 23442103721335 |
9 | 4675606733042 |
10 | 1344611001053 |
11 | 479278946601 |
12 | 198717606425 |
13 | 99a47549398 |
14 | 491182b8565 |
15 | 24e9a624888 |
hex | 139110fa2dd |
1344611001053 has 4 divisors (see below), whose sum is σ = 1367401018080. Its totient is φ = 1321820984028.
The previous prime is 1344611001047. The next prime is 1344611001077. The reversal of 1344611001053 is 3501001164431.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1344611001053 - 224 = 1344594223837 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1344611001553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11395008425 + ... + 11395008542.
It is an arithmetic number, because the mean of its divisors is an integer number (341850254520).
Almost surely, 21344611001053 is an apocalyptic number.
It is an amenable number.
1344611001053 is a deficient number, since it is larger than the sum of its proper divisors (22790017027).
1344611001053 is an equidigital number, since it uses as much as digits as its factorization.
1344611001053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22790017026.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 1344611001053 its reverse (3501001164431), we get a palindrome (4845612165484).
The spelling of 1344611001053 in words is "one trillion, three hundred forty-four billion, six hundred eleven million, one thousand, fifty-three".
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