Base | Representation |
---|---|
bin | 10000000010000… |
… | …01101011011101 |
3 | 100101001122010201 |
4 | 20001001223131 |
5 | 233412033444 |
6 | 21202303501 |
7 | 3222055435 |
oct | 1001015335 |
9 | 311048121 |
10 | 134486749 |
11 | 69a06981 |
12 | 39057b91 |
13 | 21b29a77 |
14 | 13c0b2c5 |
15 | bc17dd4 |
hex | 8041add |
134486749 has 4 divisors (see below), whose sum is σ = 138121564. Its totient is φ = 130851936.
The previous prime is 134486741. The next prime is 134486753. The reversal of 134486749 is 947684431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 71284249 + 63202500 = 8443^2 + 7950^2 .
It is a cyclic number.
It is not a de Polignac number, because 134486749 - 23 = 134486741 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 134486699 and 134486708.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134486741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1817352 + ... + 1817425.
It is an arithmetic number, because the mean of its divisors is an integer number (34530391).
Almost surely, 2134486749 is an apocalyptic number.
It is an amenable number.
134486749 is a deficient number, since it is larger than the sum of its proper divisors (3634815).
134486749 is an equidigital number, since it uses as much as digits as its factorization.
134486749 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3634814.
The product of its digits is 580608, while the sum is 46.
The square root of 134486749 is about 11596.8421994955. The cubic root of 134486749 is about 512.3418495958.
The spelling of 134486749 in words is "one hundred thirty-four million, four hundred eighty-six thousand, seven hundred forty-nine".
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