13449803 has 4 divisors (see below), whose sum is σ = 13457760. Its totient is φ = 13441848.

The previous prime is 13449767. The next prime is 13449809. The reversal of 13449803 is 30894431.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 30894431 = 107 ⋅288733.

It is a cyclic number.

It is not a de Polignac number, because 13449803 - 2¹⁴ = 13433419 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13449803.

It is not an unprimeable number, because it can be changed into a prime (13449809) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 323 + ... + 5196.

It is an arithmetic number, because the mean of its divisors is an integer number (3364440).

Almost surely, 2^13449803 is an apocalyptic number.

13449803 is a deficient number, since it is larger than the sum of its proper divisors (7957).

13449803 is an equidigital number, since it uses as much as digits as its factorization.

13449803 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7956.

The product of its (nonzero) digits is 10368, while the sum is 32.

The square root of 13449803 is about 3667.3973059924. The cubic root of 13449803 is about 237.8146698822.

The spelling of 13449803 in words is "thirteen million, four hundred forty-nine thousand, eight hundred three".