Base | Representation |
---|---|
bin | 10011100100101000111… |
… | …110011110011111111111 |
3 | 11202120201012210122220002 |
4 | 103210220332132133333 |
5 | 134014041112331033 |
6 | 2505520131544515 |
7 | 166113441215141 |
oct | 23445076363777 |
9 | 4676635718802 |
10 | 1345012230143 |
11 | 47946438099a |
12 | 198809a5b13b |
13 | 99aac6cb24a |
14 | 491556bcc91 |
15 | 24ec097c3e8 |
hex | 13928f9e7ff |
1345012230143 has 4 divisors (see below), whose sum is σ = 1424130596640. Its totient is φ = 1265893863648.
The previous prime is 1345012230119. The next prime is 1345012230151. The reversal of 1345012230143 is 3410322105431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1345012230143 - 220 = 1345011181567 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1345012230173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39559183223 + ... + 39559183256.
It is an arithmetic number, because the mean of its divisors is an integer number (356032649160).
Almost surely, 21345012230143 is an apocalyptic number.
1345012230143 is a deficient number, since it is larger than the sum of its proper divisors (79118366497).
1345012230143 is an equidigital number, since it uses as much as digits as its factorization.
1345012230143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 79118366496.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 1345012230143 its reverse (3410322105431), we get a palindrome (4755334335574).
The spelling of 1345012230143 in words is "one trillion, three hundred forty-five billion, twelve million, two hundred thirty thousand, one hundred forty-three".
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