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134501556041 = 1131190279257
BaseRepresentation
bin111110101000011101…
…0101101111101001001
3110212011122101222121122
41331100322231331021
54200424344243131
6141442243045025
712501034235306
oct1752072557511
9425148358548
10134501556041
1152050692886
1222098370775
13c8b66a4668
14671d29c0ad
15377315cd7b
hex1f50eadf49

134501556041 has 4 divisors (see below), whose sum is σ = 135691835412. Its totient is φ = 133311276672.

The previous prime is 134501556031. The next prime is 134501556047. The reversal of 134501556041 is 140655105431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 45530597641 + 88970958400 = 213379^2 + 298280^2 .

It is a cyclic number.

It is not a de Polignac number, because 134501556041 - 26 = 134501555977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134501555992 and 134501556010.

It is not an unprimeable number, because it can be changed into a prime (134501556047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595139516 + ... + 595139741.

It is an arithmetic number, because the mean of its divisors is an integer number (33922958853).

Almost surely, 2134501556041 is an apocalyptic number.

It is an amenable number.

134501556041 is a deficient number, since it is larger than the sum of its proper divisors (1190279371).

134501556041 is a wasteful number, since it uses less digits than its factorization.

134501556041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1190279370.

The product of its (nonzero) digits is 36000, while the sum is 35.

The spelling of 134501556041 in words is "one hundred thirty-four billion, five hundred one million, five hundred fifty-six thousand, forty-one".

Divisors: 1 113 1190279257 134501556041