Base | Representation |
---|---|
bin | 111110101000011101… |
… | …0101101111100111111 |
3 | 110212011122101222121021 |
4 | 1331100322231330333 |
5 | 4200424344243111 |
6 | 141442243045011 |
7 | 12501034235263 |
oct | 1752072557477 |
9 | 425148358537 |
10 | 134501556031 |
11 | 52050692877 |
12 | 22098370767 |
13 | c8b66a465b |
14 | 671d29c0a3 |
15 | 377315cd71 |
hex | 1f50eadf3f |
134501556031 has 2 divisors, whose sum is σ = 134501556032. Its totient is φ = 134501556030.
The previous prime is 134501556011. The next prime is 134501556047. The reversal of 134501556031 is 130655105431.
It is a strong prime.
It is an emirp because it is prime and its reverse (130655105431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134501556031 - 25 = 134501555999 is a prime.
It is a super-3 number, since 3×1345015560313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134501556011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67250778015 + 67250778016.
It is an arithmetic number, because the mean of its divisors is an integer number (67250778016).
Almost surely, 2134501556031 is an apocalyptic number.
134501556031 is a deficient number, since it is larger than the sum of its proper divisors (1).
134501556031 is an equidigital number, since it uses as much as digits as its factorization.
134501556031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27000, while the sum is 34.
The spelling of 134501556031 in words is "one hundred thirty-four billion, five hundred one million, five hundred fifty-six thousand, thirty-one".
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