Base | Representation |
---|---|
bin | 10011100100101110011… |
… | …001111101110000110011 |
3 | 11202120221120012121122121 |
4 | 103210232121331300303 |
5 | 134014232422302123 |
6 | 2505533144215111 |
7 | 166115625406426 |
oct | 23445631756063 |
9 | 4676846177577 |
10 | 1345103322163 |
11 | 479500838757 |
12 | 19883446a497 |
13 | 99ac5543253 |
14 | 491638319bd |
15 | 24ec897275d |
hex | 1392e67dc33 |
1345103322163 has 4 divisors (see below), whose sum is σ = 1350217783728. Its totient is φ = 1339988860600.
The previous prime is 1345103322067. The next prime is 1345103322169. The reversal of 1345103322163 is 3612233015431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1345103322163 - 213 = 1345103313971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1345103322169) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2557230388 + ... + 2557230913.
It is an arithmetic number, because the mean of its divisors is an integer number (337554445932).
Almost surely, 21345103322163 is an apocalyptic number.
1345103322163 is a deficient number, since it is larger than the sum of its proper divisors (5114461565).
1345103322163 is an equidigital number, since it uses as much as digits as its factorization.
1345103322163 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5114461564.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 1345103322163 its reverse (3612233015431), we get a palindrome (4957336337594).
The spelling of 1345103322163 in words is "one trillion, three hundred forty-five billion, one hundred three million, three hundred twenty-two thousand, one hundred sixty-three".
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