13451052240031 has 4 divisors (see below), whose sum is σ = 15372631131472. Its totient is φ = 11529473348592.

The previous prime is 13451052239981. The next prime is 13451052240053. The reversal of 13451052240031 is 13004225015431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13451052240031 - 2³⁹ = 12901296426143 is a prime.

It is a super-2 number, since 2×13451052240031² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13451052239975 and 13451052240002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13451052246031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 960789445710 + ... + 960789445723.

It is an arithmetic number, because the mean of its divisors is an integer number (3843157782868).

Almost surely, 2^{13451052240031} is an apocalyptic number.

13451052240031 is a deficient number, since it is larger than the sum of its proper divisors (1921578891441).

13451052240031 is an equidigital number, since it uses as much as digits as its factorization.

13451052240031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1921578891440.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 13451052240031 its reverse (13004225015431), we get a palindrome (26455277255462).

The spelling of 13451052240031 in words is "thirteen trillion, four hundred fifty-one billion, fifty-two million, two hundred forty thousand, thirty-one".