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1345110435301 = 1779124143253
BaseRepresentation
bin10011100100101110110…
…101000110010111100101
311202120222001121000001011
4103210232311012113211
5134014241232412201
62505534000502221
7166116043023433
oct23445665062745
94676861530034
101345110435301
11479504856986
1219883691a971
1399ac6b63ac9
1449164763d53
1524ec93ca151
hex1392ed465e5

1345110435301 has 4 divisors (see below), whose sum is σ = 1424234578572. Its totient is φ = 1265986292032.

The previous prime is 1345110435287. The next prime is 1345110435337. The reversal of 1345110435301 is 1035340115431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 384739835076 + 960370600225 = 620274^2 + 979985^2 .

It is a cyclic number.

It is not a de Polignac number, because 1345110435301 - 217 = 1345110304229 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1345110433301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39562071610 + ... + 39562071643.

It is an arithmetic number, because the mean of its divisors is an integer number (356058644643).

Almost surely, 21345110435301 is an apocalyptic number.

It is an amenable number.

1345110435301 is a deficient number, since it is larger than the sum of its proper divisors (79124143271).

1345110435301 is an equidigital number, since it uses as much as digits as its factorization.

1345110435301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79124143270.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 1345110435301 in words is "one trillion, three hundred forty-five billion, one hundred ten million, four hundred thirty-five thousand, three hundred one".

Divisors: 1 17 79124143253 1345110435301