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134515102234 = 267257551117
BaseRepresentation
bin111110101000110111…
…0011001001000011010
3110212012120220012111111
41331101232121020122
54200441331232414
6141443445250534
712501260334502
oct1752156311032
9425176805444
10134515102234
11520582a5287
12220a0a03a4a
13c8b9438366
146720dc6a02
1537744368c4
hex1f51b9921a

134515102234 has 4 divisors (see below), whose sum is σ = 201772653354. Its totient is φ = 67257551116.

The previous prime is 134515102223. The next prime is 134515102259. The reversal of 134515102234 is 432201515431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 134141260009 + 373842225 = 366253^2 + 19335^2 .

It is a junction number, because it is equal to n+sod(n) for n = 134515102196 and 134515102205.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33628775557 + ... + 33628775560.

Almost surely, 2134515102234 is an apocalyptic number.

134515102234 is a deficient number, since it is larger than the sum of its proper divisors (67257551120).

134515102234 is an equidigital number, since it uses as much as digits as its factorization.

134515102234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 67257551119.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 134515102234 its reverse (432201515431), we get a palindrome (566716617665).

The spelling of 134515102234 in words is "one hundred thirty-four billion, five hundred fifteen million, one hundred two thousand, two hundred thirty-four".

Divisors: 1 2 67257551117 134515102234