Base | Representation |
---|---|
bin | 11110100101100010110101… |
… | …000100101011001100001100 |
3 | 122122022010021121101220201100 |
4 | 132211202311010223030030 |
5 | 120112444323341043200 |
6 | 1154034141223143100 |
7 | 40222565014246641 |
oct | 3645426504531414 |
9 | 578263247356640 |
10 | 134521413612300 |
11 | 39954236022140 |
12 | 131071992a4a90 |
13 | 5a0a412a0c8a0 |
14 | 2530c2a65ddc8 |
15 | 1084326085d00 |
hex | 7a58b512b30c |
134521413612300 has 432 divisors, whose sum is σ = 495447392774880. Its totient is φ = 30097681920000.
The previous prime is 134521413612241. The next prime is 134521413612319. The reversal of 134521413612300 is 3216314125431.
134521413612300 is a `hidden beast` number, since 1 + 3 + 4 + 5 + 2 + 1 + 4 + 1 + 3 + 612 + 30 + 0 = 666.
It is a super-2 number, since 2×1345214136123002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (36).
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 801588400 + ... + 801756200.
Almost surely, 2134521413612300 is an apocalyptic number.
134521413612300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 134521413612300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (247723696387440).
134521413612300 is an abundant number, since it is smaller than the sum of its proper divisors (360925979162580).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134521413612300 is a wasteful number, since it uses less digits than its factorization.
134521413612300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174074 (or 174064 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 36.
Adding to 134521413612300 its reverse (3216314125431), we get a palindrome (137737727737731).
The spelling of 134521413612300 in words is "one hundred thirty-four trillion, five hundred twenty-one billion, four hundred thirteen million, six hundred twelve thousand, three hundred".
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