Base | Representation |
---|---|
bin | 10011100100110101101… |
… | …100001001110001001101 |
3 | 11202121021002011102220021 |
4 | 103210311230021301031 |
5 | 134020010213433240 |
6 | 2505553231422141 |
7 | 166121641225666 |
oct | 23446554116115 |
9 | 4677232142807 |
10 | 1345225530445 |
11 | 479563818635 |
12 | 198869384951 |
13 | 99b14961344 |
14 | 49175b6436d |
15 | 24ed456254a |
hex | 13935b09c4d |
1345225530445 has 4 divisors (see below), whose sum is σ = 1614270636540. Its totient is φ = 1076180424352.
The previous prime is 1345225530437. The next prime is 1345225530457. The reversal of 1345225530445 is 5440355225431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 317179596969 + 1028045933476 = 563187^2 + 1013926^2 .
It is a cyclic number.
It is not a de Polignac number, because 1345225530445 - 23 = 1345225530437 is a prime.
It is a super-2 number, since 2×13452255304452 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134522553040 + ... + 134522553049.
It is an arithmetic number, because the mean of its divisors is an integer number (403567659135).
Almost surely, 21345225530445 is an apocalyptic number.
It is an amenable number.
1345225530445 is a deficient number, since it is larger than the sum of its proper divisors (269045106095).
1345225530445 is an equidigital number, since it uses as much as digits as its factorization.
1345225530445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 269045106094.
The product of its (nonzero) digits is 1440000, while the sum is 43.
The spelling of 1345225530445 in words is "one trillion, three hundred forty-five billion, two hundred twenty-five million, five hundred thirty thousand, four hundred forty-five".
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