Base | Representation |
---|---|
bin | 10011100100110111011… |
… | …010010010011111110010 |
3 | 11202121100002111021021101 |
4 | 103210313122102133302 |
5 | 134020040111331114 |
6 | 2510000142315014 |
7 | 166122441514504 |
oct | 23446732223762 |
9 | 4677302437241 |
10 | 1345254402034 |
11 | 479579048254 |
12 | 198876b88a6a |
13 | 99b1a92c81a |
14 | 4917991bd74 |
15 | 24ed6d66d74 |
hex | 139376927f2 |
1345254402034 has 12 divisors (see below), whose sum is σ = 2073892930074. Its totient is φ = 654448086144.
The previous prime is 1345254402001. The next prime is 1345254402047. The reversal of 1345254402034 is 4302044525431.
It can be written as a sum of positive squares in 3 ways, for example, as 1344433293009 + 821109025 = 1159497^2 + 28655^2 .
It is a Harshad number since it is a multiple of its sum of digits (37).
It is a junction number, because it is equal to n+sod(n) for n = 1345254401984 and 1345254402002.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 245660959 + ... + 245666434.
Almost surely, 21345254402034 is an apocalyptic number.
1345254402034 is a deficient number, since it is larger than the sum of its proper divisors (728638528040).
1345254402034 is an equidigital number, since it uses as much as digits as its factorization.
1345254402034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 491327469 (or 491327432 counting only the distinct ones).
The product of its (nonzero) digits is 230400, while the sum is 37.
Adding to 1345254402034 its reverse (4302044525431), we get a palindrome (5647298927465).
The spelling of 1345254402034 in words is "one trillion, three hundred forty-five billion, two hundred fifty-four million, four hundred two thousand, thirty-four".
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